Question

If the point (-1/2, y) lies on the line whose equation is 2x - 3y = 6, what is the value of y?

-7/3
-5/3
7/3

Answer 1

Hi

2x - 3y = 6
-3y = -2x + 6
y = -2x/-3 + 6/-3
y = 2x/3 - 2

For x=-1/2

y = 2(-1/2)/3 - 2
y = -1/3 - 2
y = (-1-6)/3
y = -7/3

2(-1/2) = -2/2 = -1
2(-1/2)/3 = -1/3

Answer: -7/3

Answer 2

A.
`-(7)/(3)`

Explanation:

We have been given that the point
`(-(1)/(2),y)` lies on the line whose equation is
`2x-3y=6`. We are asked to find the value of y.

To find the value of y, we will substitute
`x=-(1)/(2)` in our given equation as:

`2(-(1)/(2))-3y=6`

`-1-3y=6`

`-1+1-3y=6+1`

`-3y=7`

`(-3y)/(-3)=(7)/(-3)`

`y=-(7)/(3)`

Therefore, the value of y is
`-(7)/(3)`