Question

Number 46 please last question

Answer 1

`A_(square)=(the\ side\ of\ the\ square)^2\\\\A_(square)=8100\ ft^2\ \ \ \Leftrightarrow\ \ \ A_(square)=(90\ ft)^2\\\\(the\ side\ of\ the\ square)^2=(90\ ft)^2\ \ and\ \ \ the\ side\ of\ the\ square>0\\\\the\ side\ of\ the\ square=91\ ft\\\\the\ length\ of\ the\ diagonal= √(2) \cdot the\ side\ length\ (of\ the\ square)\\\\the\ length\ of\ the\ diagonal= √(2) \cdot 90\ ft\\\\ √(2) =1.4142135623...\approx1.4142\\\\`


`\Rightarrow\ \ \ the\ length\ of\ the\ diagonal\approx1.4142\cdot90\ ft=127.278\ ft`

Answer 2

`a-the\ sides\ of\ the\ square\\\\A_{\fbox{}}=a^2;\ A_{\fbox{}}=8100ft^2\\\\a^2=8100ft^2\\\\a=√(8100ft^2)\\\\a=90ft\\---------------\\The\ diagonal\ of\ the\ square:d=a\sqrt2\\------------------\\The\ distance\ from\ home\ plate\ to\ second\ base:\\\\d=90\sqrt2\ ft\approx(90*1.414)ft=\boxed{127.26ft}`