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Solve for x 2x^2/3=dg
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4 votes
Solve for x
2x^2/3=dg

User Daniel Andrei
by
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1 Answer

5 votes
(2x²/3)=dg

2x²=3dg

x²=((3dg)/2)

So x=√((3dg)/2) or x=-√((3dg)/2)
User Ekreloff
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