Question

Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5).
-6
6
8

Answer 1

f(x) = 3x - 1
g(x) = -x + 6

f(2) + g(5) = (3(2) - 1) + (-(5) + 6)
f(2) + g(5) = (6 - 1) + (-5 + 6)
f(2) + g(5) = 5 + 1
f(2) + g(5) = 6

The answer is C.

Answer 2

This should be the answer

Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5).

f(-2) = 3(-2) =-6 -1 = -7

g(5) = -(5) = -5 +6= 1

-7+1= -6

Answer: -6