To solve this problem, you need to solve the given equation.
n+(n+2)+(n+4)=42
n+n+2+n+4=42
3n + 6 = 42
3n = 36
n=12
This means that the first starting number is 12. So the 3 consecutive even numbers would be 12, 14, and 16.
To check this, we can add these numbers together, and see if we get a sum of 42.
12+14+16=42, therefore your answer is correct.