What is the square root of 108 divided by the square root of 2q^6?? I really REALLY need the answer fast!

asked Apr 15, 2015 176k views

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$√(108):√(2q^6)=\sqrt{(108)/(2q^(3*2))}=\sqrt{(54)/((q^3)^2)}=\sqrt{(9*6)/((q^3)^2)}=(√(9*6))/(√((q^3)^2))=(\sqrt9*\sqrt6)/(q^3)=(3\sqrt6)/(q^3)$

Jeffmcneill answered Apr 16, 2015

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Answer in attachment below.... Open it up in a new window to see it in full.

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