Question

Can someone help me with this? PLs i'm so confused!

Answer 1

1. E.
`sine\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (5)/(13)`

2. L.
`cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (12)/(13)`

3.
`tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (5)/(12)`

4. Y.
`sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (5)/(13)`

5. W.
`cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (12)/(13)`

6.
`tan\ B = (b)/(a) = (adjacent)/(opposite) = (AC)/(BC) = (12)/(5) = 2(2)/(5)`

7.
`sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(2)`

8. W.
`cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (√(3))/(2)`

9. I.
`tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(√(3)) = (1)/(√(3)) * (√(3))/(√(3)) = (√(3))/(3)`

10.
`sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(2)`

11. E.
`cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (√(3))/(1) = √(3)`

12. I.
`tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(√(3)) = (1)/(√(3)) * (√(3))/(√(3)) = (√(3))/(3)`

13. U.
`sin\ A = (a)/(c) = (hypotenuse)/(opposite) = (BC)/(AB) = (12)/(15) = (4)/(5)`

14. I.
`cos\A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (9)/(15) = (3)/(5)`

15.
`tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (12)/(9) = (4)/(3) = 1(1)/(3)`

16. R.
`sin\ B = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (4)/(√(65)) = (4)/(√(65)) * (√(65))/(√(65)) = (4√(65))/(65)`

17. M.
`cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (7)/(4) = 1(3)/(4)`

18. N.
`tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (4)/(7)`

19. L.
`sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (16)/(34) = (8)/(17)`

20. H.
`cos\ B = (b)/(c) = (adjacent)/(hypotenuse) = \fac{AC}{AB} = (30)/(34) = (15)/(17)`

21.
`tan\ B = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (16)/(30) = (8)/(15)`

22. O.
`sin\ A = (a)/(c) = (opposite)/(hypotenuse) = (BC)/(AB) = (1)/(√(2)) = (1)/(√(2)) * (√(2))/(√(2)) = (√(2))/(2)`

23. O.
`cos\ A = (b)/(c) = (adjacent)/(hypotenuse) = (AC)/(AB) = (1)/(√(2)) = (1)/(√(2)) * (√(2))/(√(2)) = (√(2))/(2)`

24. N.
`tan\ A = (a)/(b) = (opposite)/(adjacent) = (BC)/(AC) = (1)/(1) = 1`