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Which quadratic equation defines the function that has zeros at -8 and 6?

User Acidernt
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Well, if 'y' has zeros at x=6 and x=-8,
then 'y' must be the product

y = (x - 6) (x + 8)

Perform the multiplication to get the quadratic function:

y = x² + 2x - 48

User Bertilio
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