193k views
4 votes
Kind people!help me please...And a detailed solution/THANKS
sin^2x-0,5sin2x=0

1 Answer

4 votes

This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent ' sin(2x) ' .
Here we go:

Original equation: Q² - 0.5 Q = 0

Factor the left side: Q (Q - 0.5) = 0

This equation is true if either factor is zero:


-- If Q=0, then sin(2x) = 0

2x = 0°, 180°, 360°

x = 0°, 90°, 180°


-- If (Q-0.5) = 0, then Q = 0.5

sin(2x) = 0.5

2x = 30°, 150°

x = 15°, 75°


The whole collection of solutions
between 0° and 360° :

x = 0°, 15°, 75°, 90°, 180° .

User Mithun Sreedharan
by
8.1k points

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