Question

Is this correct ? .......................

Answer 1

To find the midpoint of the two points (x₁ ,y₁) and (x₂, y₂) we need to use the formula:


`\sf{Midpoint=((x_1 + x_2)/(2), (y_1+y_2)/(2))}`

So to find the midpoint of E (a,a) and F (3a, a), let's plug it in to the formula:


`\sf{Midpoint=((a + 3a)/(2), (a+a)/(2))}`

Simplify the numerator:


`\sf{Midpoint=((4a)/(2), (2a)/(2))}`

Simplifying the fractions more:


`\sf{Midpoint=(2a, a)}`


So the midpoint of EF is (2a,a).

Your answer of (a,a) would be wrong.