Question

Xsquared + 3x - 5 solved using the quadratic formula

Answer 1

`x^2+3x-5=0\\a=1;\ b=3;\ c=-5\\\\ x=(-b^+_-√(b^2-4ac))/(2a)\\\\x=(-3+√(3^2-4\cdot1\cdot(-5)))/(2\cdot1)\quad\vee\quad x=(-3-√(3^2-4\cdot1\cdot(-5)))/(2)\\\\x=(-3+√(9+20))/(2)\quad\vee\quad x=(-3-√(9+20))/(2)\\\\x=(-3+√(29))/(2)\quad\vee\quad x=(-3-√(29))/(2) \\\\x\approx1.19\quad\vee\quad x\approx-4.19`