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Determine the common ratio of a geometric sequence if the second term is -4 and the fifth term is -27/2.A- -3/2B- 3/2C- -27/16D- 27/16

User Vignesh Pichamani
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1 Answer

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26 votes

A geometric sequence is a sequence in which each term is found by multiplying the preceding term by the same value. Its general term is


a_n=a_1r^(n-1)

The value r is called the common ratio.

On the sequence of our problem, we know the second and fifth term. If we substitute those values on the general term presented, we have


\begin{gathered} a_2=a_1r^(2-1)=a_1r=-4 \\ a_5=a_1r^(5-1)=a_1r^4=-(27)/(2) \end{gathered}

If we divide the fifth term by the second term, we're going to have


(a_5)/(a_2)=(a_1r^4)/(a_1r)=r^3\operatorname{\implies}r^3=((-27\/2))/((-4))

Solving for r, we have


\begin{gathered} r^3=((-27\/2))/((-4)) \\ r^3=(27)/(8) \\ r=\sqrt[3]{(27)/(8)} \\ r=(3)/(2) \end{gathered}

The common ratio is 3/2.

User Lenden
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