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(3-5i)(2+9i)+(7+2i)(7-2i)
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(3-5i)(2+9i)+(7+2i)(7-2i)

User Kartik Raja S
by
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1 Answer

3 votes

i^(2) = -1

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(3-5i)(2+9i)+(7+2i)(7-2i) = \\ \\ = 6 + 27i - 10i - 45i^(2) + 49 - 14i + 14i - 4i^(2) = \\ \\ =55 + 17i + 45 + 4 = \boxed{104 + 17i}
User Neil Foley
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