Question

If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens what is the height of the image

Answer 1

Answer:The height of the image is -6 mm.

Explanation;

Distance of the object form the lens = u = 12 mm

Distance of the image formed from the lens = v = 4 mm

Height of the object = 18 mm=
`h_o`

The magnification is given by :

`M=-(v)/(u)=(h_i)/(h_o)`

`h_i\& h_o`= Height of an image and object respectively.

`M=-(4 mm)/(12 mm)=(h_i)/(18 mm)`

`h_i=-6 mm`

The height of the image is -6 mm.The image formed is real and negative sign signifies that image is inverted.