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Equation for slope that passes through (0,4) and (1,8)

User Keturn
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1 Answer

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m = (y_(2) - y_(1))/(x_(2) - x_(1)) = (8 - 4)/(1 - 0) = (4)/(1) = 4

y - y₁ = m(x - x₁)
y - 4 = 4(x - 0)
y - 4 = 4(x) - 4(0)
y - 4 = 4x - 0
+ 4 + 4
y = 4x + 4
User Cooldude
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