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3n²-n/n²-1÷n²/n+1

User Mikku
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1 Answer

4 votes

(3n^(2) - n)/(n^(2) - 1) / (n^(2))/(n + 1)

(n(3n) - n(1))/(n^(2) + n - n - 1) / (n^(2))/(n + 1)

(n(3n - 1))/(n(n) + n(1) - 1(n) - 1(1)) / (n^(2))/(n + 1)

(n(3n - 1))/(n(n + 1) - 1(n + 1)) / (n^(2))/(n + 1)

(n(3n - 1))/((n - 1)(n + 1)) / (n^(2))/(n + 1)

(n(3n - 1))/((n - 1)(n + 1)) * (n + 1)/(n^(2))

(3n - 1)/(n - 1) * (1)/(n)

(3n - 1)/(n(n - 1))

User Sam Protsenko
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