Question

(39PTS!) Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the distance in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel?

(please show the equation and how you got it)

Answer 1

Let s = Car B's speed
Car B is 15 mph faster than A, therefore
(s-15) = Car A's speed

Write a distance equation; dist = speed time
2(s-15) = 1.5s

2s - 30 = 1.5s
2s - 1.5s = 30
.5s = 30
s = 60 mph is car B's speed

Answer 2

Let's see -

I know how to get the answer because I've had this question on one of my math assessments :)

2 × (x - 15) = 1.5 × x

2x - 30 = 1.5x

2x - 1.5x = 30

0.5x = 30

x = 0.5/30

So, x = 60 mph

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