Question

Part A Shaunice, Joshua and Juan ran several laps around the track They recorded some data based on 6 of the laps that they ran The table shows the amount of time that it took Shaunice to complete 6 of the laps that she ran What was the difference between the average pace per la for Shaunice and the average pace per lap for Joshua? Enter your answer in the box Shaunice Time Lap (seconds) 1 68 2 65 seconds per lap 3 65 4 5 6 67 70 Joshua determined his average pace to be 53 seconds per tap.

Answer 1

The average pace is computed as follows:

`\frac{total\text{ sum of }times}{\text{ number of laps}}`

Replacing with data:

`Shaunice^(\prime)s\text{ average pace per lap=}(68+65+65+64+67+70)/(6)=(399)/(6)=66.5\text{ seconds}`

The difference between Shaunice's average pace per lap and Joshua's average pace per lap is 66.5 - 63 = 3.5 seconds