Question

what is the concentration of an aqueous solution with a volume of 450 ml that contains 200 grams of iron (ll) chloride?

Answer 1

The concentration of the aqueous solution is 444.4 g/L

Step-by-step explanation:

The concentration of an aqueous solution can be calculated using the formula:

Concentration = mass of solute / volume of solution

Given that the solution contains 200 grams of iron (II) chloride and has a volume of 450 mL, we can substitute these values into the formula:

Concentration = 200 g / 450 mL

To express the concentration in grams per liter (g/L), we can convert the volume to liters:

Concentration = 200 g / 0.45 L

Simplifying this equation gives:

Concentration = 444.4 g/L

Therefore, the concentration of the solution is 444.4 g/L.

Answer 2

You are given the volume of the container which is 450mL and the number of grams of iron(III) chloride or FeCl3. You are required to get the concentration of FeCl3. The concentration pertains to the molarity of the solution with an equation of mol of solution per liter of solvent. The molar mass of FeCl3 is 162.2 g/mol. Convert grams of FeCl3 to moles.

200 g FeCl3 (1 mol FeCl3/162.2 g FeCl3) = 1.233 mol FeCl3

Then convert 450mL of solution to liters. 450mL (1 liter/1000 mL) = 0.45 L

M (molarity) = moles of solute/L of solvent
M (molarity) = 1.233 mol FeCl3/0.45 L
M (molarity) = 2.74 mol/L or 2.74M FeCl3