Question

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

Answer 1

PV=nRT

Step-by-step explanation:

T=PV/nR

P=5.6atm n= 4 mol V=12 L R =.082Latm/K mol

T= (5.6 atm)(12 L)/(4 mol)(.082Latm/K mol)

T = 205 K = -68 C

Answer 2

Okay so according to the formula PV=nRT
n=4
P=5.6 atm
V=12 L
R=0.08206 L atm mol-1 K-1
T=?
So, if you plug it in, you will get:-

T=PV/nR
T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)
T=204.73 K

Hope I'm right! :)