Question

How can I use deductive reasoning to show that

Answer 1

`In\text{ }\Delta PQS\text{ and }\Delta RQS`

`\bar{PQ}\cong\bar{RQ}`
`\angle PQS=\angle RQS\text{ (since QS bisects }\angle PQR)`
`\bar{QS}=\bar{QS}\text{ (common)}`

Therefore,

`\Delta PQS\cong\Delta RQS\text{ (SAS congruence rule.)}`

So,

`\angle P\cong\angle R`