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What is the standard form for g(x)= the square root of 6-x

User Slowkoni
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1 Answer

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The standard form of an Irrational function is given as:


\begin{gathered} y=√(a(x-p))+q \\ \text{where:} \\ y\geqslant q\text{ and x}\geqslant p \end{gathered}

In the given function:


\begin{gathered} g(x)=√(6-x) \\ \text{Domain: }\left\lbrace x\in R\colon x\leqslant6\right\rbrace \\ \text{Range: }\left\lbrace y\in R,\text{ }y\geqslant0\right\rbrace \end{gathered}

Therefore, the standard form of g(x) is:


g(x)=√(-(x-6))

User Tuncay
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