Question

A 150 mH inductor is is a circuit with a 60 Hz voltage source and a current of 1.6 A is measured on a VOM. What is the phase angle between the current and the voltage?

Answer 1

Given:

The inductance is,

`L=150\text{ mH}`

The current is,

`i=1.6\text{ A}`

The frequency of the current is,

`f=60\text{ Hz}`

To find:

The phase angle between the current and the voltage

Step-by-step explanation:

The phase angle between the current and the voltage is,

`\Phi=tan^(-1)(X_L)/(R)`

As the circuit is purely inductive,

`R=0`

The phase angle is,

`\begin{gathered} \Phi=tan^(-1)(2\pi fL)/(0) \\ \Phi=90\degree \end{gathered}`

Hence, the phase angle is 90 degrees.