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Solve the triangle below without using either the cosine or tangent ratios

Solve the triangle below without using either the cosine or tangent ratios-example-1
User Ousoo
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1 Answer

25 votes
25 votes

Given

To solve the triangle, without using either the cosine or tangent ratios.

Step-by-step explanation:

It is given that,


\theta=23\degree

By using the sine ratio, we get,


\begin{gathered} \sin23=(a)/(16) \\ a=16*\sin23 \\ a=6.25 \end{gathered}

That implies,


\begin{gathered} a^2+b^2=16^2 \\ 6.25^2+b^2=16^2 \\ 39.0625+b^2=256 \\ b^2=256-39.0625 \\ b^2=216.9375 \\ b=14.73 \end{gathered}

Hence, the answer is,


a=6.25,b=14.73

Solve the triangle below without using either the cosine or tangent ratios-example-1