Question

Calculate the number of moles in 75.0 g of dinitrogen trioxide.

Answer 1

Molar mass of dinitrogen trioxide ( N2O3 ) = 76.01 g/mol

1 mole ------------ 76.01 g
? ------------------ 75.0 g

Number of moles:

n = m / mm

n = 75.0 / 76.01

n = 0.9867 moles

hope this helps!.

Answer 2

Answer: The amount of given number of dinitrogen trioxide is 0.99 moles.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

We are given:

Given mass of dinitrogen trioxide = 75.0 g

Molar mass of dinitrogen trioxide = 76 g/mol

Putting values in above equation, we get:

`\text{Moles of dinitrogen trioxide}=(75.0g)/(76g/mol)=0.99mol`

Hence, the amount of given number of dinitrogen trioxide is 0.99 moles.