Question

How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N

Answer 1

6 Li + N2 = 2 Li3N

6 moles Li ---------> 2 moles Li3N
0.24 moles Li ------> ?

moles Li3N = 0.24 * 2 / 6

= 0.48 / 6

= 0.08 moles of li3N

hope this helps!.

Answer 2

Answer : The number of moles of
`Li_3N` will be, 0.08 moles

Solution : Given,

Moles of Li = 0.24 mole

The given balanced chemical reaction is,

`6Li+N_2\rightarrow 2Li_3N`

From the balanced reaction, we conclude that

As, 6 moles of Li react to gives 2 moles of
`Li_3N`

So, 0.24 moles of Li react to gives
`(2)/(6)* 0.24=0.08` moles of
`Li_3N`

Therefore, the number of moles of
`Li_3N` will be, 0.08 moles