Register
The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70 square feet. Find the width, w, of the rectangle algebraically. Explain why one of the solutions for w is not viable.
49.5k views
2 votes
The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70 square feet. Find the width, w, of the rectangle algebraically. Explain why one of the solutions for w is not viable.

User Sgonzalez
by
8.0k points

1 Answer

3 votes
Area = Length * Width
Length = 2w - 4
Width = w

70 = (2w - 4)w
70 = 2w² - 4w
2w² - 4w - 70 = 0
2(w² - 2w - 35) = 0
2(w + 5) (w - 7) = 0
w + 5 = 0 ; w -7 = 0
w = -5 ; w = 7

w = -5 is not viable because no length of measurement is negative.

User Abhay PS
by
8.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!