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Compare how you would model And récord finding the sum And difference of two rocks weighing 2/8 pound And 3/8 pound .

User Tal Ater
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To find the sum and difference of the two rocks, you would do:


(3)/(8) + (2)/(8) = (3+2)/(8) =\boxed{\bf{(5)/(8)}}\\\\\\ (3)/(8) - (2)/(8) = (3-2)/(8) =\boxed{\bf{(1)/(8)}}
User GertVdE
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