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Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.Lauren had brochures printed for her new business venture. She originally ordered 4 boxes of black-and-white brochures and 4 boxes of color brochures, which cost a total of $148. After those ran out, she spent $125 on 4 boxes of black-and-white brochures and 3 boxes of color brochures. Given that the prices didn't change, what was the price of each type of brochure?

User Jeff Maner
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1 Answer

19 votes
19 votes

Let the price of black and white brouchers be x

The price of color brochures be y.

A/q,

4x+4y=148.....(1)

4x+3y=125 .....(2)

The equation (1) becomes,

x+y=37

y=37-x.......(3)

Putting (3) in (2) we have,

4x+3(37-x)=125

4x+111-3x=125

x=14

Putting the value of x in (3) we have,

y=37-14=23

The price of black and white brouches is $14

The price of color brouchers is $23.

User Wolff
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