Question

Graph the line passing through (1, -5) whose slope is m = 6/5

Answer 1

We know one point and the slope. Let's use this and the slope-point form to calculate an equation for the line:

`\begin{gathered} y-(-5)=(6)/(5)(x-1)\rightarrow y+5=(6)/(5)x-(6)/(5) \\ \Rightarrow y=(6)/(5)x-(31)/(5) \end{gathered}`

Put two points that belong to the line in the plane and connect them with a line. We'll use points:

`\begin{gathered} (1,-5) \\ \text{and} \\ (6,1) \end{gathered}`

The graph would be: