Question

A function with the domain (2, 3, 4) has a specific range. Determine the function and its range. The function with the domain (2, 3, 4) is...?

A: 3x + 2
B: x + 1
And its range is...?
C: (2, 6, 8)
D: (8, 11, 14)

Answer 1

The function with the domain {2, 3, 4} is the function y = 3x + 2, making the answer equal to A.

y = 3x + 2
y = 3(2) + 2
y = 6 + 2
y = 8

y = 3x + 2
y = 3(3) + 2
y = 9 + 2
y = 11

y = 3x + 2
y = 3(4) + 2
y = 12 + 2
y = 14

I notice that the range of the function y = 3x + 2 is {8, 11, 14}, making the answer equal to D.

Answer 2

Option A and D are correct.

f(x) = 3x+2

range = {8,11, 14}

Explanation:

Domain states that all the possible values of x where function is defined

Range defined as the complete set of all values of f(x).

As per the statement:

A function with the domain (2, 3, 4) has a specific range.

To determine the function and its range.

Let function f(x) = 3x+2, then

x f(x) = 3x+2

2 8

3 11

4 14

and

Let f(x) = x+1

x f(x) = x+1

2 3

3 4

4 5

Therefore, the function with the domain {2, 3, 4} is 3x+2 and its range is {8,11, 14}