52.2k views
0 votes
A rectangle sand box has a length of 5 1/3 feet and a width of 3 3/4 feet . what is the perimeter

1 Answer

5 votes
Perimeter is 18 1/6 feet.

Perimeter is solved by adding the length and width of the rectangle and multiplying the sum by 2.

P = 2(l + w)

length = 5 1/3 ⇒ (5*3)+1/3 = 16/3
width = 3 3/4 ⇒ (3*4)+3/4 = 15/4

In adding fractions, make sure that the denominators are the same. Both 3 and 4 are factors of 12. So, we need to multiply each fraction to get 12.

16/3 * 4/4 = 64/12
15/4 * 3/3 = 45/12

Length + Width = 64/12 + 45/12 = (64+45)/12 = 109/12

P = 2 * 109/12
P = 218/12
P = 18 2/12 ⇒ 18 1/6 feet
User Patrik Simek
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories