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What two numbers multiply to get -48 and add to get 2

1 Answer

5 votes
xy = -48
x + y = 2


xy = -48

(xy)/(x) = (-48)/(x)

y = (-48)/(x)


x + y = 2

x + (-48)/(x) = 2

(x^(2))/(x) + (-48)/(x) = 2

(x^(2) - 48)/(x) = 2

2x = x^(2) - 48

0 = x^(2) - 2x - 48

x = \frac{-(-2) \± \sqrt{(-2)^(2) - 4(1)(-48)}}{2(1)}

x = (2 \± √(4 + 192))/(2)

x = (2 \± √(196))/(2)

x = (2 \± 14)/(2)

x = (1 \± 7)/(1)

x =(1 + 7)/(1)
or
x = (1 - 7)/(1)

x = (8)/(1)
or
x = (-6)/(1)

x = 8
or
x = -6

x + y = 2
8 + y = 2
- 8 - 8
y = -6
(x, y) = (8, -6)

x + y = 2
-6 + y = 2
+ 6 + 6
y = 8
(x, y) = (-6, 8)

The two numbers that multiply to -48 and add up to 2 are the numbers -6 and 8.
User Mattia Astorino
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