Question

a basketball of mass 0.23 kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a velocity of 15m/s a)calculate the impulse of the force of the wall on the basketball show your work?

Answer 1

Using the Definition of Impulse, we have:


`\Delta I=\Delta Q \\ \Delta I=m(v-v_(\circ)) \\ \Delta I=0.23(15-20) \\ \boxed {\Delta I=1.15~Ns}`

If you notice any mistake in my english, please let me know, because I am not native.