Question

The dimensions of a brick that weighs 25 N are 0.19 m × 0.07 m × 0.095 m. What pressure does the brick exert on the ground if it is resting on its largest face?

Answer 1

p - pressure [Pa]
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values ​​of bricks)

`p=(F_n)/(S)=(25N)/(0.01805m^2)=1385[Pa]`

Answer 2

The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

Step-by-step explanation:

Given that,

Weight of brick = 25 N

The dimensions of a brick are 0.19 m × 0.07 m × 0.095 m.

The pressure of the brick exert on the ground if it is resting on its largest face.

So, The area of largest face of brick is

`A = 0.19* 0.095`

`A= 0.01805\ m^2`

The pressure of the brick on the ground is

The pressure is the force upon area.

The formula of pressure is

`P =(F)/(A)`

`P=(25)/(0.01805)`

`P = 1385.04\ Pa`

Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.