Question

a 10N force is exerted on a box moving it 20m in the same direction what is the magnitude of work done on the box

Answer 1

The formula for work is
W = F*s
where W = work, F = force, s = displacement
Given that F = 10 N and s = 20 m, therefore
W = (10 N)(20 m) = 200 N*m = 200 J

Answer 2

Answer : Work done, W = 200 J.

Explanation :

Given that,

Force exerted on the box, F = 10 N

Distance covered by the box, d = 20 m

The angle between the force and the displacement is 0 as both are acting in same direction.

Work done on the box is given by :

W = F.d

`W=10\ N* 20\ m`

W = 200 J

So, the work done on the box is 200 J.

Hence, this is the required solution.