Question

I have no idea how this works, but that's not the point here. I really need help on this algebra problem;

a+bx>cx-d , solve for x.

Answer 1

a+ bx> cx -d
⇒ bx -cx > -a -d
⇒ x(b-c) > -(a+ d) (distributive property)
⇒ x > -(a+ d)/(b -c)

Final answer: x> -(a+ d)/(b -c)~

Answer 2

basically you want to make the equation so that you have
x>something or x<something so basically solve for x or isolate x so


a+bx>cx-d
try to get all the x's on one side
subtract bx from both sides
a>cx-bx-d
add d to both sides
a+d>cx-bx
undistribute
a+d>(x)(c-b)
divide both sides by (c-b)

tada


so the solution is


`(a+d)/(c-b)`>x or
x<
`(a+d)/(c-b)`