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Factoring Trinomials

25a^2+20ab+4b^2
If you don't understand I can send you a picture of the problem. :)

1 Answer

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25 a² + 20 ab + 4 b²

for formula
a^x+bx^ky^k+cy ^(2k ) find u,v such that: u.v = a

and u+v = b then group according to
(ax ^(2k) +ux^ky^k)+(vx^ky^k+cy ^(2k) )

=
(25a^2+10ab)+(10ab+4b^2)

factor out 5a from :
25a^2+10ab : 5a(2b+5a)

factor out 2b from :
10ab+4b^2: 2b(2b+5a)

=
5a(2b+5a) + 2b(2b+5a)

factor out :
(5a+2b)

=
(5a+2b)(5a+2b)

Refine:


(2b+5a)^2

hope this helps!.


User Relascope
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