Question

I need help will this besin A =a/c or the followingsin A =b/csin A =b/asin A =c/bsin A =c/asin A =a/csin A =a/b

Answer 1

`\sin \text{ A =}\frac{opposite}{\text{hypotenuse}}=\text{ }(a)/(c)`

In a right-angled triangle, the side facing the reference angle is the opposite side, the side facing the right angle is the hypotenuse

Since sinA= opposite/hypotenuse

opposite= a

hypotenuse = c

Thus, sinA= a/c