Question

What is the solution: (9x+2)(4x^2+35x-9)=0

Answer 1

`(9x+2)(4x^2+35x-9)=0\iff9x+2=0\ or\ 4x^2+35x-9=0\\\\(\#1)\\9x+2=0\ \ \ \ \ \ |subtract\ 2\ from\ both\ sides\\9x=-2\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 9\\\boxed{x=-(2)/(9)}\\\\(\#2)\\4x^2+35x-9=0\\4x^2+36x-x-9=0\\4x(x+9)-1(x+9)=0\\(x+9)(4x-1)=0\iff x+9=0\ or\ 4x-1=0\\x=-9\ or\ 4x=1\\\boxed{x=-9}\ or\ \boxed{x=(1)/(4)}\\\\Solutions:x=-(2)/(9)\ or\ x=-9\ or\ x=(1)/(4).`