Question

If King Kong fell straight down from the top of the Empire State Building (380m high), what is his velocity just before “landing”?

a 0.00 m/s
b 86.3 m/s
c -86.3 m/s
d 38.7 m/s

Answer 1

86.3m/s

Step-by-step explanation:

Given parameters:

Height = 380m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use one of the kinematic equations.

V² = U² + 2gH

V is the final velocity

U is the initial velocity = 0m/s

g is the acceleration due to gravity

H is the height

V² = 0² + (2 x 9.8 x 380) = 7448

V = 86.3m/s