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49) A car leaves town at 50 miles per hour. Two hours later, a second car, traveling 70 miles per hour, leaves along the same route as the first car. How long would it take for t…
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49) A car leaves town at 50 miles per hour. Two hours later, a second car, traveling 70 miles per hour, leaves along the same route as the first car. How long would it take for t…
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Jul 16, 2017
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49) A car leaves town at 50 miles per hour. Two hours later, a second car, traveling 70 miles per hour, leaves along the same route as the first car. How long would it take for the second car to overtake the first car?
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Let H represent the number of hours that must pass before the second car catches up with the first. This is a rate x time = distance problem.
50 m/h H = 70 m/h (H-2)
50H = 70(H-2) = 70H - 140
This is by virtue of the distributive property of multiplication over addition.
0 = 20H - 140
We subtract 50H from each side.
140 = 20H
We add 140 to each side.
7 = H
We divide each side by 20.
Seven hours is required for the two cars to encounter each other.
Brock Allen
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Jul 20, 2017
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