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If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the water?

2 Answers

2 votes

Answer:B-44

Explanation: plato

User CaptainDaVinci
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4 votes

Answer:

Distance, d = 44.1 meters

Step-by-step explanation:

It is given that, if a stone dropped into a well reaches the water's surface after 3.0 seconds, t = 3 s

We need to find the distance covered by the stone before hitting the water. Let distance covered is s. It can be calculated using second equation of motion as :


s=ut+(1)/(2)at^2

Here, u = 0 and a = g


s=0+(1)/(2)* 9.8* (3)^2

s = 44.1 meters

So, the distance covered by the stone before hitting the water is 44.1 meters. Hence, this is the required solution.

User TheExit
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8.0k points