How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?

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asked May 5, 2017 88.3k views

2 Answers

Christian Rodemeyer · Answer 1 · 2017-05-11T04:01:16+0000

The combustion reaction of hexane:

2 C6H14 + 19 O2 = 12 CO2 + 14 H2O

2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2

12 * x = 18.4 * 2

12 x = 36.8

x = 36.8 / 12

x = 3.067 moles of CO2

hope this helps!.

How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?

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