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If you sell 690 tickets and take in $46155. how many $80. tickets and how many $35. tickets would you need to sell?

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There are 489 tickets costing $80 and 201 tickets costing $35.

number of $80 ticket = x
number of $35 ticket = 690 - x

sale of $80 ticket = $80x
sale of $35 ticket = $35 (690 - x)

80x + 35(690 - x) = 46155
80x + 24150 - 35x = 46155
80x - 35x = 46155 - 24150
45x = 22005
45x / 45 = 22005 / 45
x = 489 * TICKETS COSTING $80

number of tickets costing $30 = 690 - x = 690 - 489 = 201

To check
$80 x 489 = 39120
$35 x 201 = 7035

39120 + 7035 = 46155
User Rameshwar Vyevhare
by
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