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Find the perimeter of a rectangle with sides 3x + 6 and -2x -8​

User Edbras
by
8.8k points

2 Answers

9 votes

Answer:

2x - 4

Explanation:

2(3x + 6) = 6x + 12

2(-2x - 8) = -4x -16

6x + 12 - 4x - 16 = 2x - 4

User Fabian Hueske
by
8.2k points
13 votes

Answer:

The perimeter of a rectangle with sides 3x + 6 and -2x - 8​ will be:


P = 2x - 4

Explanation:

We know that the perimeter of a rectangle of length 'l' and width 'w' is given by the formula

  • P = 2(length + width)

Given the sides of a rectangle

  • 3x + 6
  • -2x - 8​

As the opposite sides of a rectangle are congruent.

Therefore, we conclude that the Perimeter of a rectangle can be determined using the formula


\:P\:=\:2\left(3x\:+\:6\:+\:\left(-2x\:-\:8\right)\right)


=2\left(3x+6-2x-8\right)


=2\left(x-2\right)


=2x-4

Therefore, the perimeter of a rectangle with sides 3x + 6 and -2x - 8​ will be:


P = 2x - 4

User Mark Anderson
by
8.3k points

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