Question

During a chemical reaction, methane (CH^4) and oxygen (O^2) combine to produce carbon dioxide (CO^2) and water (H2O). The balanced chemical equation identifies the reactants and products for this reaction along with some of their masses. What mass (in grams) of oxygen (O^2) is required for this reaction to occur?CH^4 + 2O^2 = CO^2 + 2H^2O16 g + ???? = 44 g + 36 g

Answer 1

64 g O₂

Step-by-step explanation

Given that:

CH₄ + 2O₂ → CO₂ + 2H₂O

16 g + ? → 44 g + 36 g

What to find:

The mass of oxygen (O₂) required for the reaction to occur.

Solution:

From the given chemical equation for the reaction, 2 moles of O₂ is required.

What to do is to convert the 2 moles of O₂ to mass (in grams).

Conversion factor: 1 mole of O₂ = 32 g

If 1 mole of O₂ = 32 g

Then 2 moles of O₂ = 2 x 32 g = 64 g.

Hence, 64 g of oxygen (O₂) is required for the reaction to occur.

CH₄ + 2O₂ → CO₂ + 2H₂O

16 g + 64 g → 44 g + 36 g