Question

What is the pendulum length whose period is 2.0s ?

Answer 1

`Formula\ for\ period:\\\ T=2 \pi \sqrt{(L)/(g)}\\\ g-gravity=9,8 (m)/(s^2) ,\ L-pendulum \ length \\\\ (T)/(2 \pi ) = \sqrt{ (L)/(g) }|square\\\\ (T^2)/(2 \pi ) = (L)/(g) \\\\\ (T^2)/(2 \pi )*g=L\\\\ L= (2^2)/(2*3,14 )*9,8= (39,2)/(6,28) =6,24m`
`T=2 \pi \sqrt{(L)/(g)} \\ (T)/(2 \pi ) = \sqrt{ (L)/(g) }|square\\ (T^2)/(2 \pi ) = (L)/(g) \\ (T^2)/(2 \pi )*g=L\\ L= (2^2)/(2*3,14 )*9,8= (39,2)/(6,28) =6,24m`