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Find the equation of a line passing through (5, -6) parallel to: (a) 2x + y = 12 (b) 3x + 5y = 7 (c) x + 3y = 8 (d) 7x - 12y = 5 2y = 5 (e) r = 7 (f)

User James Mitchell
by
2.2k points

1 Answer

14 votes
14 votes

ANSWER

y = -2x + 4

Step-by-step explanation

a. We want to find the equation of the line that is parallel to the given equation and passes through (5, -6):

2x + y = 12

Let us put the equation in the slope-intercept form:

y = -2x + 12

When two lines are parallel, their slopes are equal.

The general form of a linear equation is:

y = mx + c

where m = slope

c = intercept

This means that the slope of the given equation is -2. Therefore, the slope of the equation we need is also -2.

Now, we can apply the point-slope method to find the equation of the line.

We have:

y - y1 = m(x - x1)

where (x1, y1) is a point that lies on the line

m = slope

(x1, y1) => (5, -6).

Therefore:

y - (-6) = -2(x - 5)

y + 6 = -2x + 10

=> y = -2x + 10 - 6

y = -2x + 4

That is the equation of the line that passes through (5, -6) and is parallel to the given equation.

User Ignas Damunskis
by
3.0k points
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