Question

=Matt (m = 80 kg) and Trey (m= 90 kg) slide across an ice skating rink and collidewith each other. Before the collision, Matt was moving 3 m/s to the east and Treywas moving 2 m/s to the west. After the collision, Matt is moving 1.5 m/s to thewest. What is the total momentum of the system after the collision

Answer 1

Answer:

The total momentum after collision = 60 kgm/s

Step-by-step explanation:
`\begin{gathered} \text{Mass of Matt, m}_m=\text{ 80kg} \\ \text{Mass of Trey, m}_t=\text{ 90 kg} \end{gathered}`

Before the collision:

Matt was moving 3 m/s to the east and Trey was moving 2 m/s to the west

`\begin{gathered} \text{Initial speed of Matt, u}_m=\text{ 3m/s} \\ \text{Initial speed of Trey, u}_t=\text{ -2m/s (Since it is an opposite direction)} \end{gathered}`

According to the principle of momentum conservation:

The total momentum before collision = The total momentum after collision

`\begin{gathered} \text{Total momentum before collision = m}_mu_m+m_tu_t \\ \text{Total momentum before collision = 80(3) + 90(-2)} \\ \text{Total momentum before collision = 240 - 180} \\ \text{Total momentum before collision = 60 kgm/s} \end{gathered}`

Since the total momentum before collision = Total momentum after collision

The total momentum after collision = 60 kgm/s